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Algorithmic Thinking in Bioinformatics End Term: 31 August 2025 (May 2025 term)

Question 1

+5 marksOne correct option

We run the RANDOMIZEDMOTIFSEARCH algorithm on the following set of DNA strings with k=4k = 4.

Dna=TACCTATGTCCGGCGACTAA\mathit{Dna} = \begin{matrix} \text{TACCT} \\ \text{ATGTC} \\ \text{CGGCG} \\ \text{ACTAA} \end{matrix}

During some iteration of the algorithm, the profile matrix on the chosen 4-mers are given below.

PROFILE(Motifs)=A:0.40.20.20.2C:0.20.40.20.2G:0.20.20.40.2T:0.20.20.20.4\text{PROFILE}(\mathit{Motifs}) = \begin{matrix} \text{A:} & 0.4 & 0.2 & 0.2 & 0.2 \\ \text{C:} & 0.2 & 0.4 & 0.2 & 0.2 \\ \text{G:} & 0.2 & 0.2 & 0.4 & 0.2 \\ \text{T:} & 0.2 & 0.2 & 0.2 & 0.4 \end{matrix}

Which of the following can be the set of motifs that are chosen for the next iteration?

  1. A

    TACC, ATGT, CGGC, ACTA

  2. B

    ACCT, TGTC, GGCG, CTAA

  3. C

    TACC, TGTC, GGCG, CTAA

  4. D

    ACCT, ATGT, CGGC, ACTA

Question 2

+5 marksOne correct option

The theoretical spectrum of the peptide "GAS" is

0 57 71 87 128 144 158 215

Given below in Figure 1 is the partially filled table to compute the spectral convolution. Complete the table and determine which among the following masses have the minimum multiplicity.

0577187128144158
0
5757
717114
878716
12812841
14414416
15815814
215215158144128877157

Figure 1: Partially filled Spectral Convolution Table

  1. A

    14

  2. B

    41

  3. C

    57

  4. D

    128

Question 3

+5 marksNumerical answer

Consider the alignment graph based DP table below to find the best global alignment between two strings (represented along the rows and the columns). The DP table shown below has n×mn \times m entries i.e., DP[0,0]DP[0,0] to DP[n,m]DP[n,m], where nn is length of first string and mm is length of second string. DP[i,j]DP[i,j] is the score of best global alignment between the length-ii prefix of the first string and length-jj prefix of the second string.

Fill the DP table given below and answer the following questions accordingly.

GTACA
G
A
C
A
T

Scoring is done as follows:

  • For each match between two symbols: +1+1 point
  • For each mismatch between two symbols: 00 point
  • For each removal of symbol from any one sequence: 00 point

How many entries in the grid consists of the number 3? Enter the answer as a single integer.

13 more questions in this paper

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More on the Algorithmic Thinking in Bioinformatics End Term 31 Aug 2025 paper

The IIT Madras BS Algorithmic Thinking in Bioinformatics (Algorithmic Thinking in Bioinformatics) End Term paper sat on 31 Aug 2025, in the May 2025 term: 16 questions for 53 marks in 180 minutes. The first 3 questions are below. Sign in with Google — it is free — to see the whole paper with its answers and explanations, in learning mode or as a timed mock test.

FeatureAlgorithmic Thinking in Bioinformatics End Term 31 Aug 2025 at a glance
TermMay 2025 term
SubjectAlgorithmic Thinking in Bioinformatics
Course codeBSBT4001
Questions16
Marks53
Duration180 min
MCQ5
Numerical10
MSQ1
Official paperIIT M IMPROVEMENT FN EXAM QIA1 31 Aug 2025
Negative markingNo negative marking.
Updated

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