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Mathematical Thinking End Term: 24 December 2023 (September 2023 term)

Question 1

+18 marksOne correct option

1 Section I (18 Marks)

  1. True or False? [2 marks]

If aa is relatively prime to nn then gcd⁡(n−a,n)=1\gcd(n - a, n) = 1.

  1. What is the digit in the units place in the decimal expansion of 21002^{100}? [2 marks]

  2. Let GG be the graph on five vertices with adjacency matrix

[0101110100010101010110010]\begin{bmatrix} 0 & 1 & 0 & 1 & 1 \\ 1 & 0 & 1 & 0 & 0 \\ 0 & 1 & 0 & 1 & 0 \\ 1 & 0 & 1 & 0 & 1 \\ 1 & 0 & 0 & 1 & 0 \end{bmatrix}

Which of the following hold for GG? [3 marks]

(a) The degree of every vertex in the graph is 2.
(b) GG has six edges.
(c) GG is three-colourable.
(d) GG is planar.

  1. Consider the function f:R⟶Rf : \mathbb{R} \longrightarrow \mathbb{R} defined by

f(x)={∣(x−1)(x−3)∣x−3,if x≠32,if x=3f(x) = \begin{cases} \frac{|(x-1)(x-3)|}{x-3}, & \text{if } x \neq 3 \\ 2, & \text{if } x = 3 \end{cases}

Which of the following options is/are true? [3 marks]

(a) lim⁡x→3+f(x)=f(3)\lim\limits_{x \to 3^+} f(x) = f(3).
(b) lim⁡x→3−f(x)=f(3)\lim\limits_{x \to 3^-} f(x) = f(3).
(c) f(2)=−1f(2) = -1.
(d) ff is continuous at x=3x = 3.

  1. Evaluate lim⁡θ→0sin⁡(5θ)sin⁡(4θ)\lim\limits_{\theta \to 0} \dfrac{\sin(5\theta)}{\sin(4\theta)}. [2 marks]

  2. Consider the function f:R→Rf : \mathbb{R} \to \mathbb{R} defined by (x)=∣x−1∣+∣x∣(x) = |x - 1| + |x|. Which of the following options is/are true? [3 marks]

(a) The function f(x)f(x) is continuous at x=0x = 0 and x=1x = 1.
(b) The function f(x)f(x) is differentiable at x=0x = 0 and x=1x = 1.
(c) The function f:R→Rf : \mathbb{R} \to \mathbb{R} is surjective.
(d) The function f:R→Rf : \mathbb{R} \to \mathbb{R} is injective.

  1. Let f(x)=6x2+4xf(x) = 6x^2 + 4x be a function defined in the interval [0,6][0, 6]. Compute the Mid-Riemann sum of the function ff by dividing the interval [0,6][0, 6] into 3 sub-intervals of equal length and using the midpoints of the sub-intervals for the height of the rectangles. [3 marks]
  1. A

    I have written answers on the answer sheets

  2. B

    Not applicable

Question 2

+17 marksOne correct option

2 Section II (17 Marks)

  1. Use the Intermediate Value Theorem to prove that the equation x5=20+xx^5 = 20 + \sqrt{x} has a solution in the interval [1,4][1, 4]. [3 marks]

  2. Let f(x)=cos⁡(sin⁡(x))f(x) = \cos(\sin(x)). Compute the third derivative f′′′(x)f'''(x). [4 marks]

  3. Discuss the convergence of the sequence {xn}n≥1\{x^n\}_{n \geq 1}, where xx is any positive real number, treating each of the cases x>1x > 1, x=1x = 1, and 0<x<10 < x < 1 separately. [5 marks]

  4. Let {Fn}\{F_n\} be the usual Fibonacci sequence defined by

F1=F2=1 and Fn=Fn−1+Fn−2 for n>2.F_1 = F_2 = 1 \text{ and } F_n = F_{n-1} + F_{n-2} \text{ for } n > 2.

Define a new sequence {Gn}\{G_n\} by

G1=4,G2=3 and Gn=Gn−1+Gn−2 for n>2.G_1 = 4, G_2 = 3 \text{ and } G_n = G_{n-1} + G_{n-2} \text{ for } n > 2.

Using the principle of mathematical induction, prove that

Gn=3Fn−1+4Fn−2G_n = 3F_{n-1} + 4F_{n-2}

for all n>2n > 2. [5 marks]

  1. A

    I have written answers on the answer sheets

  2. B

    Not applicable

More on the Mathematical Thinking End Term 24 Dec 2023 paper

The IIT Madras BS Mathematical Thinking (Mathematical Thinking) End Term paper sat on 24 Dec 2023, in the September 2023 term: 2 questions for 35 marks in 180 minutes. The first 2 questions are below. Sign in with Google — it is free — to see the whole paper with its answers and explanations, in learning mode or as a timed mock test.

FeatureMathematical Thinking End Term 24 Dec 2023 at a glance
TermSeptember 2023 term
SubjectMathematical Thinking
Course codeBSMA2001
Questions2
Marks35
Duration180 min
MCQ2
Official paperIIT M DEGREE FN EXAM FDB1 24 Dec 2023
Negative markingNo negative marking.
Updated

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