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September 2023 term · Mathematical Thinking · BSMA2001

Mathematical Thinking End Term: 24 December 2023 (September 2023 term)

The IIT Madras BS Mathematical Thinking (Mathematical Thinking) End Term paper sat on 24 Dec 2023, in the September 2023 term: 2 questions for 35 marks in 180 minutes. Every question is below with its answer. Take it as a timed mock test to be marked, or read it through first.

Questions
2
Marks
35
Duration
180 min
MCQ
2

Updated

Official paper: IIT M DEGREE FN EXAM FDB1 24 Dec 2023 · No negative marking.

Question 1

+18 marksOne correct option

1 Section I (18 Marks)

  1. True or False? [2 marks]

If aa is relatively prime to nn then gcd⁡(n−a,n)=1\gcd(n - a, n) = 1.

  1. What is the digit in the units place in the decimal expansion of 21002^{100}? [2 marks]

  2. Let GG be the graph on five vertices with adjacency matrix

[0101110100010101010110010]\begin{bmatrix} 0 & 1 & 0 & 1 & 1 \\ 1 & 0 & 1 & 0 & 0 \\ 0 & 1 & 0 & 1 & 0 \\ 1 & 0 & 1 & 0 & 1 \\ 1 & 0 & 0 & 1 & 0 \end{bmatrix}

Which of the following hold for GG? [3 marks]

(a) The degree of every vertex in the graph is 2.
(b) GG has six edges.
(c) GG is three-colourable.
(d) GG is planar.

  1. Consider the function f:R⟶Rf : \mathbb{R} \longrightarrow \mathbb{R} defined by

f(x)={∣(x−1)(x−3)∣x−3,if x≠32,if x=3f(x) = \begin{cases} \frac{|(x-1)(x-3)|}{x-3}, & \text{if } x \neq 3 \\ 2, & \text{if } x = 3 \end{cases}

Which of the following options is/are true? [3 marks]

(a) lim⁡x→3+f(x)=f(3)\lim\limits_{x \to 3^+} f(x) = f(3).
(b) lim⁡x→3−f(x)=f(3)\lim\limits_{x \to 3^-} f(x) = f(3).
(c) f(2)=−1f(2) = -1.
(d) ff is continuous at x=3x = 3.

  1. Evaluate lim⁡θ→0sin⁡(5θ)sin⁡(4θ)\lim\limits_{\theta \to 0} \dfrac{\sin(5\theta)}{\sin(4\theta)}. [2 marks]

  2. Consider the function f:R→Rf : \mathbb{R} \to \mathbb{R} defined by (x)=∣x−1∣+∣x∣(x) = |x - 1| + |x|. Which of the following options is/are true? [3 marks]

(a) The function f(x)f(x) is continuous at x=0x = 0 and x=1x = 1.
(b) The function f(x)f(x) is differentiable at x=0x = 0 and x=1x = 1.
(c) The function f:R→Rf : \mathbb{R} \to \mathbb{R} is surjective.
(d) The function f:R→Rf : \mathbb{R} \to \mathbb{R} is injective.

  1. Let f(x)=6x2+4xf(x) = 6x^2 + 4x be a function defined in the interval [0,6][0, 6]. Compute the Mid-Riemann sum of the function ff by dividing the interval [0,6][0, 6] into 3 sub-intervals of equal length and using the midpoints of the sub-intervals for the height of the rectangles. [3 marks]
  1. A

    I have written answers on the answer sheets

  2. B

    Not applicable

Show answer

Correct answer

  • A

    I have written answers on the answer sheets

Question 2

+17 marksOne correct option

2 Section II (17 Marks)

  1. Use the Intermediate Value Theorem to prove that the equation x5=20+xx^5 = 20 + \sqrt{x} has a solution in the interval [1,4][1, 4]. [3 marks]

  2. Let f(x)=cos⁡(sin⁡(x))f(x) = \cos(\sin(x)). Compute the third derivative f′′′(x)f'''(x). [4 marks]

  3. Discuss the convergence of the sequence {xn}n≥1\{x^n\}_{n \geq 1}, where xx is any positive real number, treating each of the cases x>1x > 1, x=1x = 1, and 0<x<10 < x < 1 separately. [5 marks]

  4. Let {Fn}\{F_n\} be the usual Fibonacci sequence defined by

F1=F2=1 and Fn=Fn−1+Fn−2 for n>2.F_1 = F_2 = 1 \text{ and } F_n = F_{n-1} + F_{n-2} \text{ for } n > 2.

Define a new sequence {Gn}\{G_n\} by

G1=4,G2=3 and Gn=Gn−1+Gn−2 for n>2.G_1 = 4, G_2 = 3 \text{ and } G_n = G_{n-1} + G_{n-2} \text{ for } n > 2.

Using the principle of mathematical induction, prove that

Gn=3Fn−1+4Fn−2G_n = 3F_{n-1} + 4F_{n-2}

for all n>2n > 2. [5 marks]

  1. A

    I have written answers on the answer sheets

  2. B

    Not applicable

Show answer

Correct answer

  • A

    I have written answers on the answer sheets